12x^2-216x+655=0

Solution for 12x^2-216x+655=0 equation:

12x^2-216x+655=0

a = 12; b = -216; c = +655;
Δ = b2-4ac
Δ = -2162-4·12·655
Δ = 15216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15216}=\sqrt{16*951}=\sqrt{16}*\sqrt{951}=4\sqrt{951}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-216)-4\sqrt{951}}{2*12}=\frac{216-4\sqrt{951}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-216)+4\sqrt{951}}{2*12}=\frac{216+4\sqrt{951}}{24}
$